Y represents the character whose position you want to obtain. X represents the string that contains the character whose position you want to obtain. Z represents the character or string that is used to replace Y.įinds the position of a character in a string Y represents the character or substring you want to replace. X represents the string that contains the character or string you want to replace. Replaces a character or substring in your string with another character or string REPLACE('column name', 'replace_this', 'with_this') Returns the number of characters in the string LOWER(X)Ĭonverts the string to all lowercase letters UPPER(X)Ĭonverts the string to all uppercase letters REPLACE(X, Y, Z) There are many core functions that you can use for strings and numeric values, but here are some of the common ones you can use for strings: LENGTH(X) INNER JOIN CTE_Start c ON h.RowId = c.Atlassian Analytics uses SQLite to power the non-query Visual SQL steps. WHERE (NumberStart NumberEnd) OR (NumberStart = 0 AND NumberEnd = 0) INNER JOIN CTE_End_Sum e ON s.RowId = e.RowId SELECT ISNULL(s.RowId, e.RowId) as RowId, NumberStart, NumberEnd SELECT e.RowId, SUM(e.Occurrence) as NumberEnd SELECT s.RowId, SUM(s.Occurrence) as NumberStart INNER JOIN CTE_End c ON h.RowId = c.RowId INNER JOIN CTE_Start c ON h.RowId = c.RowId Occurrence = CASE WHEN CHARINDEX (, , 0 ) > 0 THEN 1 ELSE 0 END,

Insert into dbo.tblHTML values ( 5, '>xxxxxx' )

Insert into dbo.tblHTML values ( 4, '>xxx' ) Insert into dbo.tblHTML values ( 3, '>xxxyyyzzz' ) Insert into dbo.tblHTML values ( 2, 'xxxyyyzzz' ) Insert into dbo.tblHTML values ( 1, 'wwwxxxyyyzzz' ) I've set MAXRECURSION to 10, but you can increase this if necessary. I've elected to show rows where both values are zero in case these are wrong - You can remove this if you want. HAVING COUNT(lastStartpos) COUNT(lastEndpospos) SELECT RowID, TagStarts = COUNT(lastStartpos), TagEnds = COUNT(lastEndpospos) WHERE NOT (lastStartpos IS NULL OR lastEndpospos IS NULL) LastEndpospos = NULLIF(CHARINDEX('',strPage,lastEndpospos+1),0) LastStartpos = NULLIF(CHARINDEX('',strPage,lastStartpos+1),0), LastEndpospos = NULLIF(CHARINDEX('',q.strPage,1),0)ĬROSS APPLY (SELECT strPage = CAST(strPage AS VARCHAR(MAX))) q LastStartpos = NULLIF(CHARINDEX('',q.strPage,1),0), SELECT *, LEN(CAST(strPage AS VARCHAR(MAX))) FROM #tblHTML + '' + 'I have a table with an ntext column that has HTML in it ' + 'xxxxxxxx'

+ REPLICATE('I have a table with an ntext column that has HTML in it ',25)Ģ, REPLICATE(CAST('I have a table with an ntext column that has HTML in it ' AS VARCHAR(MAX)),25) + '' + 'I have a table with an ntext column that has HTML in it ' + '' Then I found a post here at SQL Sever Central and I eagerly made a number table to use with it, but then I realized it returns a total count for the column, not the individual records that contain the string.Ĭan you please help me or point me in the right direction? Thank you!ĬREATE TABLE #tblHTML (RowID INT, strPage ntext)ġ, REPLICATE(CAST('I have a table with an ntext column that has HTML in it ' AS VARCHAR(MAX)),25) I found some solutions that involve using LEN and REPLACE ( like this one) but those do not seem to work because 'Argument data type ntext is invalid for argument 1 of replace function.' I've looked for 3 hours now, and I haven't found anyone else with my exact issue - to return a count for each record of the number of occurrences of a string in an ntext field. If the number of '' strings does not equal the number of '' strings, then return the id of that record as part of the recordset. figure out how many occurrences of '' and '' there are in each record's. I need to find those records so I can fix them.ġ. I have a table with an ntext column that has HTML in it.Įach record's field text should contain an equal number of '' and '' strings.īut some do not.

Sqlite count occurrences in column